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5x^2+5x+4=42
We move all terms to the left:
5x^2+5x+4-(42)=0
We add all the numbers together, and all the variables
5x^2+5x-38=0
a = 5; b = 5; c = -38;
Δ = b2-4ac
Δ = 52-4·5·(-38)
Δ = 785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{785}}{2*5}=\frac{-5-\sqrt{785}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{785}}{2*5}=\frac{-5+\sqrt{785}}{10} $
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